How much heat must be extracted from the room?
mass air x specific heat air x DT.
549200 g x 1.2 x 6.8 = ??
322.106 g of the salt will extract 74.7. You want to know how much it will take to extract ??.
Check my work.
Glauber's salt undergoes a phase transition according to the following equation:
Na2SO4*10H2O(s)--> Na2SO4*10H2O(l) DH = 74.4 kJ/mol
Calculate the mass (g) of Glauber's salt (use the masses to two decimal places found in the front of your text) needed to lower the temperature of air in a room by 6.8oC. The mass of air in the room is 549.2 kg; the specific heat of air is 1.2J/g-C.
2 answers
how did you get 322.106 g?
1 answer