1) y = x^2 - 2x - 3
Solution: To find the solution, we set y = 0 and solve for x.
0 = x^2 - 2x - 3
0 = (x - 3)(x + 1)
x = 3 or x = -1
Sketch of the graph:
The graph is a parabola that opens upwards with x-intercepts at x = 3 and x = -1.
2) y = -2x^2 + 4x + 1
Solution: Setting y = 0 and solving for x,
0 = -2x^2 + 4x + 1
Using the quadratic formula, x = 1.7071 or x = -0.7071
Sketch of the graph:
The graph is a parabola that opens downwards with x-intercepts at x = 1.7071 and x = -0.7071.
3) y = 3x^2 - 6x - 9
Solution: Setting y = 0 and solving for x,
0 = 3x^2 - 6x - 9
0 = x^2 - 2x - 3
0 = (x - 3)(x + 1)
x = 3 or x = -1
Sketch of the graph:
The graph is a parabola that opens upwards with x-intercepts at x = 3 and x = -1.
4) y = 5x^2 + 2x - 3
Solution: Setting y = 0 and solving for x,
0 = 5x^2 + 2x - 3
Using the quadratic formula, x = 0.6 or x = -1.0
Sketch of the graph:
The graph is a parabola that opens upwards with x-intercepts at x = 0.6 and x = -1.0.
5) y = -4x^2 - 8x + 4
Solution: Setting y = 0 and solving for x,
0 = -4x^2 - 8x + 4
0 = x^2 + 2x - 1
Using the quadratic formula, x = 0.4142 or x = -2.4142
Sketch of the graph:
The graph is a parabola that opens downwards with x-intercepts at x = 0.4142 and x = -2.4142.
Gives 5 examples of general second degree of equations and find the solution and sketch the graph?
1 answer