Given:

Vi=0m/s
d=15m
t=3.25s
Find
a=?
d=Vi+1/2 at^2

1 answer

We can use the equation of motion d = Vi*t + (1/2)*a*t^2 to solve for a.

Given:
Vi = 0 m/s (initial velocity)
t = 3.25 s (time)
d = 15 m (displacement)

Using the equation: d = Vi*t + (1/2)*a*t^2

15 = (0)*(3.25) + (1/2)*a*(3.25)^2

This simplifies to:

15 = 0 + (1/2)*a*(10.5625)

Rearranging the equation:

(1/2)*a*(10.5625) = 15

Dividing both sides by (1/2)*10.5625:

a = 15 / (0.5 * 10.5625)

a = 15 / 5.28125

a ≈ 2.841 m/s^2

Therefore, the acceleration is approximately 2.841 m/s^2.