Given two spheres, if the volume of the first sphere is 36r, and the volume of the second sphere is 288r, what is the relation of the second radius to the first radius?

1 answer

V1 = (4pi/3)r^3 = 36r,
Divide both sides by r:
(4pi/3)r^2 = 36,
Multiply both sides by 3/4pi:
r^2 = 36 * 3/4pi,
r^2 = 27/pi = 8.59,
r = 2.93.

V2 = (4pi/3)r^3 = 288r,
(4pi/3)r^2 = 288,
r^2 = 288(3/4pi) = 216/pi = 68.75,
r = 8.29.

r2/r1 = 8.29/2.93 = 2.83,
r2 = 2.83r1.
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