If SU┴TP, SU=8 (think 3-4-5 triangle)
Since the area is 1/2 bh using any side as a base, the other two altitudes can be found via
8*12 = 10h
Given: ΔTSP, TS = SP = 10cm, TP = 12cm. Find: Three altitudes of ΔTSP.
for this one I only got one of the altitudes
2 √61
can you give me the other two and tell me if this one is right, sorry I am in a rush
3 answers
So how what would be all 3?
answer is: 9.6,9.6, and 8