Given triangleABC proportion to trianglePQR. If AB=4cm, BC=6cm, AC=9cm, and QR=4cm, find the perimeter of trianglePQR. What is the ratio of similitude?

3 answers

since the common sides have a constant ratio,

AB/PQ = BC/QR = CA/SP
4/PQ = 6/4 = 9/SP
the ratio is 6/4 = 3/2

so, the perimeters are also in that ratio, and
P(ABC) = 4+6+9 = 19
P(PQR) = 19 * 3/2
Two supplementary angles are in the ratio 5:7. Find the larger angle
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Supplementary angles sum up to 180 degrees.

Taking the larger one as 7x, the smaller one is 5x (they are in a 5:7 ratio)

=> 5x + 7x = 180
=> 12x = 180
=> x = 15

Hence, the larger angle = 7x = 7(15) = 105