Given triangle JKL on the coordinate plane. There is y on the top and x on the right side. Those are labeled on the lines. The triangle is at the top right, right in the y and x that is labeled. The triangle is a scalene triangle, except the top is bigger and wider and its taller. It had three point, the top point being J, the right bottom point being K, and the left bottom point being L. What is the length side of JK? What is the length side of LK? What is the length side of JL? What is the perimeter of the triangle JKL in simplest radical form?

1 answer

To calculate the lengths of the sides of triangle JKL, we need the specific coordinates of points J, K, and L. However, since those coordinates were not provided in your question, I’ll create a general approach based on arbitrary coordinates for vertices J, K, and L in the coordinate plane.

Let’s assume we have the following coordinates for each vertex:

  • Point J (top) = (x1, y1)
  • Point K (bottom right) = (x2, y2)
  • Point L (bottom left) = (x3, y3)

The lengths of the sides of the triangle can be calculated using the distance formula:

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

Length of sides:

  1. Length of Side JK: \[ JK = \sqrt{(x2 - x1)^2 + (y2 - y1)^2} \]

  2. Length of Side KL: \[ KL = \sqrt{(x3 - x2)^2 + (y3 - y2)^2} \]

  3. Length of Side JL: \[ JL = \sqrt{(x3 - x1)^2 + (y3 - y1)^2} \]

Perimeter of triangle JKL:

The perimeter \( P \) can be calculated by summing the lengths of the sides:

\[ P = JK + KL + JL \]

Example:

Assuming some arbitrary coordinates:

  • J(1, 5)
  • K(4, 1)
  • L(2, 2)
  1. Calculate JK: \[ JK = \sqrt{(4 - 1)^2 + (1 - 5)^2} = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \]

  2. Calculate KL: \[ KL = \sqrt{(2 - 4)^2 + (2 - 1)^2} = \sqrt{(-2)^2 + 1^2} = \sqrt{4 + 1} = \sqrt{5} \]

  3. Calculate JL: \[ JL = \sqrt{(2 - 1)^2 + (2 - 5)^2} = \sqrt{1^2 + (-3)^2} = \sqrt{1 + 9} = \sqrt{10} \]

Perimeter:

\[ P = JK + KL + JL = 5 + \sqrt{5} + \sqrt{10} \]

Thus, if you provide the specific coordinates of points J, K, and L, I can compute the lengths of the sides and the perimeter more accurately.