Given the thermochemical equation:

2ZnS(s) + 3O2(g) „³ 2ZnO(s) + 2SO2(g) £GH = --879 kJ
Calculate the heat evolved (in kJ) when 560 grams of ZnS is converted to ZnO.

Please explain throughly with answers.

2 answers

879 kJ are released when 2 moles (97.46 x 2 = 194.92 g) are used. So 560 g converted will be proportional to that.
879 kJ x (560g/194.92 g) = ?? kJ.
-136kj