To determine the high or low point of the parabola defined by the quadratic equation \( y = -6x^2 + 3x + 8 \), we first recognize that this parabola opens downwards (since the coefficient of \( x^2 \) is negative), indicating that it has a high point (maximum), rather than a low point (minimum).
The high point (vertex) of a parabola in standard form \( y = ax^2 + bx + c \) can be found using the formula:
\[ x = -\frac{b}{2a} \]
In this case, \( a = -6 \) and \( b = 3 \):
\[ x = -\frac{3}{2 \times -6} = -\frac{3}{-12} = \frac{1}{4} = 0.25 \]
Next, we can find the corresponding \( y \) value by substituting \( x = 0.25 \) back into the equation:
\[ y = -6(0.25)^2 + 3(0.25) + 8 \] \[ = -6(0.0625) + 0.75 + 8 \] \[ = -0.375 + 0.75 + 8 \] \[ = 0.375 + 8 \] \[ = 8.375 \]
So, the vertex (the high point) of the parabola is at the point \( (0.25, 8.375) \).
Now, examining the provided options, the statement that matches our finding is:
(0.25, 8.375) is the high point on the parabola.
Thus, that would be the correct response.