To find the high or low point of the parabola represented by the quadratic equation \( y = -6x^2 + 3x + 8 \), we need to determine the vertex of the parabola. Since the leading coefficient (the coefficient of \( x^2 \)) is negative, this parabola opens downwards, meaning it has a maximum (high point).
The x-coordinate of the vertex can be found using the formula: \[ x = -\frac{b}{2a} \] where \( a = -6 \) and \( b = 3 \):
\[ x = -\frac{3}{2 \times -6} = -\frac{3}{-12} = \frac{1}{4} = 0.25 \]
Next, we can substitute \( x = 0.25 \) back into the equation to find the corresponding \( y \)-value:
\[ y = -6(0.25)^2 + 3(0.25) + 8 \] Calculating \( (0.25)^2 \): \[ = 0.0625 \]
Now substituting: \[ y = -6(0.0625) + 3(0.25) + 8 \] \[ = -0.375 + 0.75 + 8 \] \[ = 8.375 \]
So, the vertex of the parabola, which is the high point, is at \( (0.25, 8.375) \).
Now, let's look at your response options:
- (−1,−1) is the low point on the parabola.
- (0.25,8.375) is the low point on the parabola.
- (0.5,9) is the high point on the parabola.
- (0.25,8.375) is the high point on the parabola.
The correct answer based on our calculations is: (0.25, 8.375) is the high point on the parabola.