To determine the high or low point of the parabola represented by the equation \( y = -6x^2 + 3x + 8 \), we first need to calculate the vertex of the parabola, since the vertex will give us either the highest or lowest point, depending on the orientation of the parabola.
The formula for the x-coordinate of the vertex of a quadratic function in the form \( y = ax^2 + bx + c \) is given by:
\[ x = -\frac{b}{2a} \]
In this case:
- \( a = -6 \)
- \( b = 3 \)
Substituting in these values:
\[ x = -\frac{3}{2 \times -6} = -\frac{3}{-12} = \frac{1}{4} = 0.25 \]
Next, we substitute \( x = 0.25 \) back into the quadratic equation to find the corresponding \( y \)-coordinate:
\[ y = -6(0.25)^2 + 3(0.25) + 8 \] \[ y = -6(0.0625) + 0.75 + 8 \] \[ y = -0.375 + 0.75 + 8 \] \[ y = 8.375 \]
So, the vertex of the parabola is \( (0.25, 8.375) \).
Since the coefficient of \( x^2 \) (which is -6) is negative, the parabola opens downward, meaning that the vertex represents a high point.
Thus, the correct option is:
(0.25, 8.375) is the high point on the parabola.