Given the recursive formula for the geometric sequence a^1=5a^n=2/5a^n-1 find the second term of the sequence.(1 point)

Responses

a2=8/5

a2=2/5

a2=2

a2=5 2/5

1 answer

To find the second term of the geometric sequence given the recursive formula \( a^1 = 5 \) and \( a^n = \frac{2}{5} a^{n-1} \), we start by calculating the second term \( a^2 \).

  1. We know \( a^1 = 5 \).
  2. Using the recursive formula for \( n = 2 \): \[ a^2 = \frac{2}{5} a^{1} \] Substituting \( a^1 = 5 \) into the equation: \[ a^2 = \frac{2}{5} \cdot 5 \] Simplifying: \[ a^2 = \frac{2 \cdot 5}{5} = 2 \]

Thus, the second term of the sequence is \( a^2 = 2 \).

The correct response is:

a2=2

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