To find the second term of the geometric sequence given the recursive formula \( a^1 = 5 \) and \( a^n = \frac{2}{5} a^{n-1} \), we start by calculating the second term \( a^2 \).
- We know \( a^1 = 5 \).
- Using the recursive formula for \( n = 2 \): \[ a^2 = \frac{2}{5} a^{1} \] Substituting \( a^1 = 5 \) into the equation: \[ a^2 = \frac{2}{5} \cdot 5 \] Simplifying: \[ a^2 = \frac{2 \cdot 5}{5} = 2 \]
Thus, the second term of the sequence is \( a^2 = 2 \).
The correct response is:
a2=2