Given the reaction: Fe2SiO4 (s) + 2 H2CO3 (aq) ----> 2FeCO3 (s) + H4SiO4 (aq). How many grams of Fe2SiO4 are required to completely react with 55.0 mL of .500 M H2CO3 (aq)?
2 answers
1.29g
1. You have the balanced equation.
2. mols H2CO3 = M x L = ?
3. Using the coefficients in the balanced equation, convert mols H2CO3 to mols Fe2SiO4.
4. Now convert mols Fe2SiO4 to grams. g = mols x molar mass = ?
2. mols H2CO3 = M x L = ?
3. Using the coefficients in the balanced equation, convert mols H2CO3 to mols Fe2SiO4.
4. Now convert mols Fe2SiO4 to grams. g = mols x molar mass = ?