To find the missing \(y\) values in the table for the quadratic equation \(y = 3x^2 - 6x + 9\), we can substitute each \(x\) value into the equation to find the corresponding \(y\) values.
Given Values
Let's fill in the table step-by-step.
-
For \(x = -3\):
\[
y = 3(-3)^2 - 6(-3) + 9
\]
\[
= 3(9) + 18 + 9 = 27 + 18 + 9 = 54
\]
(confirming the value is correct).
-
For \(x = -2\):
\[
y = 3(-2)^2 - 6(-2) + 9
\]
\[
= 3(4) + 12 + 9 = 12 + 12 + 9 = 33
\]
(confirming the value is correct).
-
For \(x = -1\):
\[
y = 3(-1)^2 - 6(-1) + 9
\]
\[
= 3(1) + 6 + 9 = 3 + 6 + 9 = 18
\]
-
For \(x = 0\):
\[
y = 3(0)^2 - 6(0) + 9
\]
\[
= 0 + 0 + 9 = 9
\]
-
For \(x = 1\):
\[
y = 3(1)^2 - 6(1) + 9
\]
\[
= 3(1) - 6 + 9 = 3 - 6 + 9 = 6
\]
-
For \(x = 2\):
\[
y = 3(2)^2 - 6(2) + 9
\]
\[
= 3(4) - 12 + 9 = 12 - 12 + 9 = 9
\]
Table Completion
Here's the completed table:
\[
\begin{array}{|c|c|}
\hline
x & y \
\hline
-3 & 54 \
-2 & 33 \
-1 & 18 \
0 & 9 \
1 & 6 \
2 & 9 \
\hline
\end{array}
\]
Finding the High or Low Point
To find the vertex (high or low point) of the parabola represented by the equation \(y = 3x^2 - 6x + 9\), we can use the vertex formula, where the \(x\)-coordinate of the vertex is given by:
\[
x = -\frac{b}{2a}
\]
For our equation, \(a = 3\) and \(b = -6\):
\[
x = -\frac{-6}{2 \cdot 3} = \frac{6}{6} = 1
\]
Now, substituting \(x = 1\) back into the equation to find \(y\):
\[
y = 3(1)^2 - 6(1) + 9 = 3 - 6 + 9 = 6
\]
Conclusion
The high or low point of this parabola (the vertex) is:
\((1, 6)\).