AB = 5
BC = √40
AC = √85, so
85 = 25+40-2(5)(√40)cos(ABC)
20 = -20√10 cos(ABC
cos(ABC) = -1/√10
ABC = 108.43°
Given the points A(0,0), B(4, 3) and C(2,9), what is the measure of angle ABC?
Using Law of Cosines.
1 answer
0 answers