Given the linear equation 5y = -3x + 19, find

(a) the slope of a line perpendicular to the given line.
(b) the slope of a line parallel to the given line.

A. (a) -5/3 (b) 3/5
B. (a) -3/5 (b) 5/3
C. (a) 5/3 (b)-3/5
D. (a) 3/5 (b)-5/3

1 answer

Rewrite the equation as:
y=(-3/5)x + 19/5
which makes the slope as (-3/5)

Lines that are parallel have the same slope.

Two lines that are perpendicular to each other have the product of the slope equal to -1.

That should be enough for you to make the right choice.
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