Given the information below, calculate the heat provided by combustion of 66.1g of propane (C3H8). ΔHf° (C3H8(g)) = -103.85 kJ ΔHf° (CO2(g)) = -393.5 kJ ΔHf° (H2O(ℓ)) = -285.8 kJ Can Someone explain this in detail? i have to answer this type of problems on my test.

Answer 1

C3H8 + 5O2 ==> 3CO2 + 4H2O
dHrxn = (n*dHf products) - (n*dHf reactants)