reverse second C⟶D ΔH∘= 465.0 kJ ΔS∘= −188.0J/kg
d⟶c ΔH∘= -5.0 kJ ΔS∘= 188.0J/K
doubling the values to get 2D >>2C
then add the similar values to the first given equation
Given the information
A+B⟶2D ΔH∘=−764.7kJ ΔS∘=328.0 J/K
C⟶D ΔH∘= 465.0 kJ ΔS∘= −188.0J/K
calculate ΔG∘ at 298 K for the reaction
A+B⟶2C ΔG∘=
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