Given the graph of a linear function, find the linear equation of the graph in point-slope form. What is the missing value needed to finish the point-slope form of the equation?

The point-slope form of the equation is y-___ = -3 (x-1)

1 answer

To complete the point-slope form of the equation given as \( y - __ = -3(x - 1) \), we need to find the y-coordinate of the point through which the line passes.

In point-slope form, the equation is written as:

\[ y - y_1 = m(x - x_1) \]

where \( m \) is the slope and \( (x_1, y_1) \) is a point on the line. In this case, the slope \( m = -3 \) and the x-coordinate of the point is \( x_1 = 1 \).

Thus, we need to find \( y_1 \), the y-coordinate corresponding to \( x_1 = 1 \). Since we do not have the graph or additional information about the linear function, we can't find the exact value of \( y_1 \) through inspection.

However, if you provide a specific point on the graph or the value of \( y \) at \( x = 1 \), we can then substitute that value into your equation.

For example, if the point on the graph is (1, 4), then \( y_1 = 4 \) and the complete equation would be:

\[ y - 4 = -3(x - 1) \]

So we currently have the y-coordinate \( y_1 = __ \). If additional specific information about the graph or the y-value at \( x = 1 \) is available, please provide that, and we can complete the equation.