g(f) = 4f-1 = 4(x^2+2) - 1 = 4x2 + 7
f(g) = g^2+2 = (4x-1)^2 + 2 = 16x^2 - 8x + 3
Your answer, 16x^2 + 3 = f(g+1) + 3
Given the functions, f(x) = x2 + 2 and g(x) = 4x - 1, perform the indicated operation. When applicable, state the domain restriction.
g(f(x))
4 x2 + 1
16 x2 + 3
4 x2 + 7
16 x2 - 8 x + 3
Please help. I thinks that it is 16 x2 + 3. Thanks
1 answer