f(g(x)) = f(x+1) = √(x+1)
g(f(x)) = g(√x) = √x + 1
so √(x+1) = √x + 1
by observation, I can see that x=0 is a solution, ....
square both sides
x+1 = x + 2√x + 1
0 = 2√x
x = 0
(my intuition was correct)
Given the functions f(x)=sqrt[x] and g(x)=x+1, determine all possible values of x for which f(g(x)) = g(f(x)). Show steps please, thanks a lot!
3 answers
Where did you get the x+2 from?
(sqrt x + 1)^2 = x + 2 sqrt x + 1