f(x)=(x^2+6x+5)/(x^2+3x−10)
= (x+1)(x+5(/((x+5)(x-2) )
= (x+1)/(x-2)
domain: any real value of x , x ≠ -5, 2
vertical asymptote:
x = 2
hole:
x = -5
horizontal asymptote:
y = 1
see:
http://www.wolframalpha.com/input/?i=plot+y+%3D+%28x%5E2%2B6x%2B5%29%2F%28x%5E2%2B3x−10%29+
notice the graph cannot show the hole at x = -5
Given the function:
f(x)=(x^2+6x+5)/(x^2+3x−10)
Find the
Domain:
Vertical asymptote(s):
Hole(s):
Horizontal asymptote (if exists):
1 answer