Given the function f, of, x, equals, minus, x, squared, minus, 2, x, plus, 3f(x)=−x

2
−2x+3, determine the average rate of change of the function over the interval minus, 6, is less than or equal to, x, is less than or equal to, 2−6≤x≤2

1 answer

To determine the average rate of change of the function \( f(x) = -x^2 - 2x + 3 \) over the interval \([-6, 2]\), we can use the formula for the average rate of change:

\[ \text{Average rate of change} = \frac{f(b) - f(a)}{b - a} \]

where \( a = -6 \) and \( b = 2 \).

First, we need to calculate \( f(-6) \) and \( f(2) \).

Calculating \( f(-6) \):

\[ f(-6) = -(-6)^2 - 2(-6) + 3 \] \[ = -36 + 12 + 3 \] \[ = -36 + 15 \] \[ = -21 \]

Calculating \( f(2) \):

\[ f(2) = -(2)^2 - 2(2) + 3 \] \[ = -4 - 4 + 3 \] \[ = -8 + 3 \] \[ = -5 \]

Now that we have both function values, we can calculate the average rate of change:

\[ \text{Average rate of change} = \frac{f(2) - f(-6)}{2 - (-6)} \] \[ = \frac{-5 - (-21)}{2 + 6} \] \[ = \frac{-5 + 21}{8} \] \[ = \frac{16}{8} \] \[ = 2 \]

Thus, the average rate of change of the function \( f(x) \) over the interval \([-6, 2]\) is \( \boxed{2} \).