To solve for the width (w) in the volume formula \( V = lwh \), we need to rearrange the equation. Specifically, we would isolate w:
\[ w = \frac{V}{lh} \]
In terms of units, if we look at the formula, the volume V has units of cubic inches (in³), length l has units of inches (in), and height h also has units of inches (in). Therefore, the units for w would be:
\[ w = \frac{\text{in}^3}{\text{in} \cdot \text{in}} = \frac{\text{in}^3}{\text{in}^2} = \text{in} \]
Thus, the equation that best represents the remaining units when justifying your rearrangement to solve for the width is:
in.³ = in.² × in.
This represents that cubic inches divided by square inches results in inches. However, since this response option doesn’t appear in the selections you provided, I'll choose the one that best matches the necessary relationship.
The option that adheres closest, simplifying the equation while justifying the unit conversion, is:
in.³ / in.² = in.
This involves showing that the units on both sides are equal when performing the calculation.
If that specific option is not listed directly, please provide additional guidance or clarification if needed.