To solve for the width \( w \) in the formula for the volume of a box \( V = lwh \), we can rearrange it to isolate \( w \). The formula can be rearranged as follows:
\[ w = \frac{V}{lh} \]
In terms of units, the volume \( V \) is in cubic inches (\( \text{in}^3 \)), and the dimensions \( l \) and \( h \) are in inches (\( \text{in} \)). Thus, when you divide \( V \) by \( lh \), the units would be:
\[ w = \frac{\text{in}^3}{\text{in} \cdot \text{in}} = \frac{\text{in}^3}{\text{in}^2} = \text{in} \]
The equation that best represents the remaining units when justifying your rearrangement to solve for the width \( w \) is:
\[ \frac{\text{in}^3}{\text{in}^2} = \text{in} \]
So the correct response is:
in.3/in.2=in.
Start Fraction in. cubed over in. squared End Fraction equals in.
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