To rearrange the formula for the volume of a box \( V = lwh \) to solve for the width \( w \), we start by isolating \( w \):
- Rearranging the equation gives us \( w = \frac{V}{l \cdot h} \).
Now, let's analyze the units on both sides of the equation:
- The volume \( V \) is measured in cubic inches (in³).
- The length \( l \) and height \( h \) are both measured in square inches (in²).
When we substitute these units into the equation for \( w \):
\[ w = \frac{in^3}{in^2} \]
This simplifies to:
\[ w = in \]
Thus, the units for width is inches (in), confirming that our rearrangement is correct.
The equation that best represents the remaining units when justifying this rearrangement is:
Start Fraction in. cubed over in. squared End Fraction equals in.
So, the correct response is: Start Fraction in. cubed over in. squared End Fraction equals in.