given the fonction: y=3x^2-5x and x=g(t)derivable as g(14)=-4 and g'(14)=2

Question

calculate dy/dt in t = 14

Answer 1

y = 3x^2 - 5x
= 3(g(t)^2 - 5g(t)

dy/dt = 6 g(t) d(g(t))/dt - 5 d(g(t))/dt
= 6(g(14)) d(g(14))/dt - 5 d(g(14))/dt
= 6(-4)(2) - 5(2)
= -58