Given the following two step reaction:

Question

4 P + 5 O2 -> P4O10

P4O10 + 6 H2O -> 4H3PO4

If you have 8.28 g of P, 15.65 g of O2, and 19.95 g of H2O, how many grams of H3PO4 can be produced?

Answer 1

4 P + 5 O2 -> P4O10
8.28g 15.65g
moles=g/mw x=15.65g/160.0
x=8.28/124.0 x= 0.0978
x=0.067

Which one would be limited? Please help if possible. Also, are my sigfigs correct?

Answer 2

4 P
8.28g
m=g/mw
x=8.28/124.0
x=0.067

+ 502
15.65g
x=15.65g/160
x= 0.0978

= P4O10

Answer 3

See the post above where I worked part of the problem.

Answer 4

40.9 grams produce