Do you mean you want to determine which way the cell is spontaneous?
Add an oxidation half to a reduction half, the one that ends up with a positive Ecell is spontaneous. If I have misinterpreted the question, please clarify.
Given the following two half-reactions, determine which overall reaction is spontaneous and calculate its standard cell potential.
Cd^2+(aq) + 2e^- ==> Cd(s) E naught = -1.21V
Sn^2+ + 2e^- ==Sn(s) E naught = -0.14V
2 answers
Sn^2+ +Cd(s) ==> Sn(s) + Cd^2+
delta e prime-naught will be 1.07V
delta e prime-naught will be 1.07V
3 answers