Given the following two half reactions: Cd²⁺(aq) + 2e⁻ → Cd(s) E° = -0.40 V; Zr⁴⁺ (aq) + 4e⁻ → Zr(s) E° = -1.53 V. Determine E° and the spontaneity of the following reaction: 2 Cd²⁺(aq) + Zr(s) → 2 Cd(s) + Zr⁴⁺ (aq)

Answer 1

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