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Given the following sets, select the statement below that is true.
A = {r, i, s, k, e, d}, B = {r, i, s, e}, C = {s, i, r}
(Points : 2)
B ⊂ A and B ⊂ C
A ⊂ C and C ⊂ B
B ⊆ A and C ⊂ A
C ⊆ A and B ⊆ C
A ⊆ B and C ⊆ B
B ⊂ A means that every element found in B is found in A, but B≠A, i.e. B is a proper subset of A.
If B can equal A, the symbol ⊆ is used.
For example, elements in B are r,i,s and e. Each of the four elements are also found in A which has a higher cardinality than B. So B ⊂ A is true.
On the other hand, the cardinality of B is 4, while that of C is 3. So B⊂C is not possible. So the first statement is false.
You can continue this way, and post your results for checking if you wish.
Given the following sets, select the statement below that is true.
A = {r, i, s, k, e, d}, B = {r, i, s, e}, C = {s, i, r}
(Points : 2)
B �¼ A and B �¼ C
A �¼ C and C �¼ B
B �º A and C �¼ A
C �º A and B �º C
A �º B and C �º B
1 answer