HCl(g) + SrO(s) -> SrCl2(s) + H2O
start with balancing the equation, which will look like this
aHCl(g) + SrO(s) -> cSrCl2(s) + dH2O
This will give you the number of moles of HCl (a) that react with one mole of SrO
calculate the number of moles of SrO in 11.44 kg from
11440/(molar mass of SrO)
the equation will then tell you how many moles of HCl that react with one mole of SrO (=a).
so number of moles of HCl is
11440x(a)/(molar mass of SrO)
mass of HCl is
11440x(a)x(molar mass of HCl)/(molar mass of SrO)
Given the following reaction:
HCl(g) + SrO(s) �¨ SrCl2(s) + H2O
Calculate the mass of HCl in grams that would react with 11.44 kg SrO.
1 answer
1 answer