Given the following reaction:

HCl(g) + SrO(s) �¨ SrCl2(s) + H2O
Calculate the mass of HCl in grams that would react with 11.44 kg SrO.

1 answer

HCl(g) + SrO(s) -> SrCl2(s) + H2O

start with balancing the equation, which will look like this

aHCl(g) + SrO(s) -> cSrCl2(s) + dH2O

This will give you the number of moles of HCl (a) that react with one mole of SrO

calculate the number of moles of SrO in 11.44 kg from

11440/(molar mass of SrO)

the equation will then tell you how many moles of HCl that react with one mole of SrO (=a).

so number of moles of HCl is

11440x(a)/(molar mass of SrO)

mass of HCl is

11440x(a)x(molar mass of HCl)/(molar mass of SrO)
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