a long division shows that
F(x) = 1/2 - (x+2)/(2(2x^2-x-2))
so, as x gets large, F(x) -> 1/2
vertical asymptotes where 2x^2-x-2=0
no oblique asymptotes.
Given the following rational function, find
a) the horizontal asymptote(s),
b) the vertical asymptote(s), if any, and
c) the oblique asymptote(s), if any.
F(x) = x^2-x-2/2x^2-x-2
1 answer