Given the following quadratic equation find.

Question

a) the vertex
b) the axis of symmetry
c) the intercepts
d) the domain
e) the range
f) the interval where the function is increasing
g) the interval where the function is decreasing
h) graph the function
y= -x^2-6x

Answer 1

Y = -x^2 - 6x.

a. h = Xv = -b/2a = 6/-2 = -3
k = -(-3)^2 - 6*-3 = 9
V(h,k)=(-3,9).

b. Axis = h = Xv = -3.

c. Y = -x^2 - 6x = 0.
x(-x-6) = 0
X = 0 = x-Intercept.
-x-6 = 0
X = -6. = X-Intercept.

d. Domain = All real values of X.

e.

f. X = -6 to -3.

g. X = -3 to 0.

h. Use the following points for graphing:

(X,Y)
(-5,5)
(-4,8)
V(-3,9)
(-2,8)
(-1,5).