Given the following quadratic equation find.

a) the vertex
b) the axis of symmetry
c) the intercepts
d) the domain
e) the range
f) the interval where the function is increasing
g) the interval where the function is decreasing
h) graph the function
y= -x^2-6x

1 answer

Y = -x^2 - 6x.

a. h = Xv = -b/2a = 6/-2 = -3
k = -(-3)^2 - 6*-3 = 9
V(h,k)=(-3,9).

b. Axis = h = Xv = -3.

c. Y = -x^2 - 6x = 0.
x(-x-6) = 0
X = 0 = x-Intercept.
-x-6 = 0
X = -6. = X-Intercept.

d. Domain = All real values of X.

e.

f. X = -6 to -3.

g. X = -3 to 0.

h. Use the following points for graphing:

(X,Y)
(-5,5)
(-4,8)
V(-3,9)
(-2,8)
(-1,5).
Similar Questions
  1. I really need help on some sample work. Just need to check my answers:1. Describe how the graph of y=-x^2+1 differs from y=x^2.
    1. answers icon 1 answer
  2. I really need help on some sample work. Just need to check my answers:1. Describe how the graph of y=-x^2+1 differs from y=x^2.
    1. answers icon 5 answers
    1. answers icon 1 answer
  3. Use the graph of the function to identify the vertex and axis of symmetry(1 point) Responses axis of symmetry: X= 2, vertex (2,
    1. answers icon 1 answer
more similar questions