The smallest extreme value is 3.
The largest extreme value is 58.
Given the following dataset, what are the extremes?
58, 32, 8, 25, 13, 12, 3, 11, 22, 10(1 point)
The smallest extreme value is
.
The largest extreme value is
.
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8 answers
Given the following dataset, what is the first quartile? Round to the nearest tenth if necessary.
42, 82, 67, 34, 54, 62, 17, 47, 56, 18, 20(1 point)
42, 82, 67, 34, 54, 62, 17, 47, 56, 18, 20(1 point)
To find the first quartile, we need to first order the data from smallest to largest:
17, 18, 20, 34, 42, 47, 54, 56, 62, 67, 82
The first quartile is the median of the lower half of the data. In this case, the lower half of the data is 17, 18, 20, 34, 42. Since there is an odd number of data points in the lower half, the median of the lower half is the middle value, which is 20.
Therefore, the first quartile is 20.
17, 18, 20, 34, 42, 47, 54, 56, 62, 67, 82
The first quartile is the median of the lower half of the data. In this case, the lower half of the data is 17, 18, 20, 34, 42. Since there is an odd number of data points in the lower half, the median of the lower half is the middle value, which is 20.
Therefore, the first quartile is 20.
The amounts of rainfall measured in inches in downtown Los Angeles during the six rainy seasons from 2000 to 2006 are given as a dataset.
15.56, 4.16, 10.38, 8.61, 26.51, 10.89
Find the range of this dataset.
(1 point)
The range of this dataset is
.
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15.56, 4.16, 10.38, 8.61, 26.51, 10.89
Find the range of this dataset.
(1 point)
The range of this dataset is
.
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To find the range of a dataset, you subtract the smallest value from the largest value.
In this dataset, the smallest value is 4.16 and the largest value is 26.51.
So, the range of this dataset is:
26.51 - 4.16 = 22.35
Therefore, the range of the dataset is 22.35 inches.
In this dataset, the smallest value is 4.16 and the largest value is 26.51.
So, the range of this dataset is:
26.51 - 4.16 = 22.35
Therefore, the range of the dataset is 22.35 inches.
The average temperatures in December in Washington, D.C., from 1993 to 1998 are given as a dataset.
38.1, 44.2, 35.6, 43.0, 41.0, 44.4
Find the interquartile range of the dataset.
(1 point)
The interquartile range of the dataset is
.
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38.1, 44.2, 35.6, 43.0, 41.0, 44.4
Find the interquartile range of the dataset.
(1 point)
The interquartile range of the dataset is
.
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To find the interquartile range (IQR) of a dataset, you first need to find the first quartile (Q1) and the third quartile (Q3), then subtract Q1 from Q3.
Given dataset: 38.1, 44.2, 35.6, 43.0, 41.0, 44.4
Step 1: Order the dataset from least to greatest:
35.6, 38.1, 41.0, 43.0, 44.2, 44.4
Step 2: Find the median of the dataset. Since we have an even number of values (6), the median is the average of the two middle values:
(41.0 + 43.0) / 2 = 42.0
Step 3: Q1 is the median of the lower half of the data:
Lower half: 35.6, 38.1, 41.0
Median of lower half: (38.1 + 41.0) / 2 = 39.55
Step 4: Q3 is the median of the upper half of the data:
Upper half: 43.0, 44.2, 44.4
Median of upper half: (44.2 + 44.4) / 2 = 44.3
Step 5: Calculate the IQR by subtracting Q1 from Q3:
IQR = Q3 - Q1
IQR = 44.3 - 39.55
IQR ≈ 4.75
Therefore, the interquartile range of the dataset is approximately 4.75.
Given dataset: 38.1, 44.2, 35.6, 43.0, 41.0, 44.4
Step 1: Order the dataset from least to greatest:
35.6, 38.1, 41.0, 43.0, 44.2, 44.4
Step 2: Find the median of the dataset. Since we have an even number of values (6), the median is the average of the two middle values:
(41.0 + 43.0) / 2 = 42.0
Step 3: Q1 is the median of the lower half of the data:
Lower half: 35.6, 38.1, 41.0
Median of lower half: (38.1 + 41.0) / 2 = 39.55
Step 4: Q3 is the median of the upper half of the data:
Upper half: 43.0, 44.2, 44.4
Median of upper half: (44.2 + 44.4) / 2 = 44.3
Step 5: Calculate the IQR by subtracting Q1 from Q3:
IQR = Q3 - Q1
IQR = 44.3 - 39.55
IQR ≈ 4.75
Therefore, the interquartile range of the dataset is approximately 4.75.
what's the exact answer bot GPT?
17 answers