To solve the equation \( \sin(3x + 10°) = \cos(2x - 10°) \) using the relationship between sine and cosine for complementary angles, we can use the fact that \( \sin(θ) = \cos(90° - θ) \).
So, \[ \sin(3x + 10°) = \cos(2x - 10°) \implies 3x + 10° = 90° - (2x - 10°) \]
Now, simplify the equation: \[ 3x + 10° = 90° - 2x + 10° \] \[ 3x + 10° = 100° - 2x \]
Now, add \( 2x \) to both sides: \[ 3x + 2x + 10° = 100° \] \[ 5x + 10° = 100° \]
Next, subtract \( 10° \) from both sides: \[ 5x = 90° \]
Finally, divide by 5: \[ x = 18° \]
Thus, the correct answer is: 18°.