Asked by eeeeee
Given the equation y=3x2−24x+48 with solutions of x=4 and x=4, which of the following identifies the general shape of its associated graph?(1 point) Responses The vertex is to the left of the y-axis. The vertex is to the left of the y -axis. The entire graph lies above the x-axis. The entire graph lies above the x -axis. The graph opens upward. The graph opens upward. The graph opens downward.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To analyze the quadratic equation \( y = 3x^2 - 24x + 48 \), we can identify several key characteristics that determine the shape of the graph:
1. **Direction of the Opening**: The coefficient of \( x^2 \) (which is 3) is positive. This means that the graph opens upward.
2. **Vertex Position**: We can find the vertex of a quadratic equation given by \( ax^2 + bx + c \) using the formula for the x-coordinate of the vertex, which is \( x = -\frac{b}{2a} \). Here, \( a = 3 \) and \( b = -24 \):
\[
x = -\frac{-24}{2(3)} = \frac{24}{6} = 4
\]
The x-coordinate of the vertex is 4, which is to the right of the y-axis.
3. **Position Relative to the x-axis**: To determine if the entire graph lies above the x-axis, we can check the y-coordinate of the vertex. We can substitute \( x = 4 \) back into the equation to find \( y \):
\[
y = 3(4)^2 - 24(4) + 48
\]
\[
= 3(16) - 96 + 48
\]
\[
= 48 - 96 + 48
\]
\[
= 0
\]
The vertex is at the point (4, 0), meaning that the graph touches the x-axis at this point, but does not lie entirely above it.
Given these points, we can summarize:
- The graph **opens upward**,
- The vertex is at \( x = 4 \) (to the right of the y-axis),
- The graph does not lie entirely above the x-axis; it touches the x-axis at the vertex.
Thus the most relevant answer choices are:
- **The graph opens upward.**
This is the correct option regarding the general shape of the associated graph.
1. **Direction of the Opening**: The coefficient of \( x^2 \) (which is 3) is positive. This means that the graph opens upward.
2. **Vertex Position**: We can find the vertex of a quadratic equation given by \( ax^2 + bx + c \) using the formula for the x-coordinate of the vertex, which is \( x = -\frac{b}{2a} \). Here, \( a = 3 \) and \( b = -24 \):
\[
x = -\frac{-24}{2(3)} = \frac{24}{6} = 4
\]
The x-coordinate of the vertex is 4, which is to the right of the y-axis.
3. **Position Relative to the x-axis**: To determine if the entire graph lies above the x-axis, we can check the y-coordinate of the vertex. We can substitute \( x = 4 \) back into the equation to find \( y \):
\[
y = 3(4)^2 - 24(4) + 48
\]
\[
= 3(16) - 96 + 48
\]
\[
= 48 - 96 + 48
\]
\[
= 0
\]
The vertex is at the point (4, 0), meaning that the graph touches the x-axis at this point, but does not lie entirely above it.
Given these points, we can summarize:
- The graph **opens upward**,
- The vertex is at \( x = 4 \) (to the right of the y-axis),
- The graph does not lie entirely above the x-axis; it touches the x-axis at the vertex.
Thus the most relevant answer choices are:
- **The graph opens upward.**
This is the correct option regarding the general shape of the associated graph.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.