Given the equation y=3x2−24x+48 with solutions of x=4 and x=4, which of the following identifies the general shape of its associated graph?(1 point)

Responses

The entire graph lies above the x-axis.
The entire graph lies above the x -axis.

The vertex is to the left of the y-axis.
The vertex is to the left of the y -axis.

The graph opens upward.
The graph opens upward.

The graph opens downward.

1 answer

To determine the general shape of the graph for the equation \( y = 3x^2 - 24x + 48 \), we can analyze the quadratic equation.

  1. Determine the vertex and direction of opening: The standard form of a quadratic equation is \( y = ax^2 + bx + c \). In this case, \( a = 3 \). Since \( a > 0 \), the graph opens upward.

  2. Find the vertex: The x-coordinate of the vertex can be found using the formula \( x = -\frac{b}{2a} \).

    • Here, \( b = -24 \) and \( a = 3 \).
    • \( x = -\frac{-24}{2 \times 3} = \frac{24}{6} = 4 \).
  3. Evaluate the vertex position: The vertex occurs at \( x = 4 \), which is to the right of the y-axis.

  4. Roots of the equation: The given solutions (or roots) are \( x = 4 \) and \( x = 4 \), meaning the graph touches the x-axis at one point (the vertex) but does not go below it.

With this analysis, the graph:

  • Opens upward.
  • The entire graph is above the x-axis except for the vertex point.

Given the options:

  • The graph opens upward.

Thus, the correct response is: The graph opens upward.