Given the equation y=−2x+2, what is the slope? Write your answer as an integer.(1 point)
The slope is
13 answers
-2
Given the equation y=34x−2 what is the y-intercept? Write your answer as an ordered pair.(1 point)
The y-intercept is (
).
The y-intercept is (
).
The y-intercept is (0, -2).
Using the graph, derive the equation of the line in slope-intercept form.
(1 point)
Responses
y=3x−4
y equals 3 x minus 4
y=3x+4
y equals 3 x plus 4
y=−3x−4
y equals negative 3 x minus 4
3x−y=4
(1 point)
Responses
y=3x−4
y equals 3 x minus 4
y=3x+4
y equals 3 x plus 4
y=−3x−4
y equals negative 3 x minus 4
3x−y=4
Based on the graph, the equation of the line in slope-intercept form is y=3x-4.
Write the equation of the line in slope-intercept form.
(1 point)
Responses
y=5x+1
y equals 5 x plus 1
y=−5x+1
y equals negative 5 x plus 1
y=−5x−1
y equals negative 5 x minus 1
−5x−y=−1
(1 point)
Responses
y=5x+1
y equals 5 x plus 1
y=−5x+1
y equals negative 5 x plus 1
y=−5x−1
y equals negative 5 x minus 1
−5x−y=−1
Based on the given information, the equation of the line in slope-intercept form is y=5x+1.
Graph the linear equation y=−3x+2.
To graph the equation y = -3x + 2, we can plot a few points and then connect them to form a line.
One way to plot points is by substituting values of x into the equation and calculating the corresponding y-values.
Let's choose a few values for x and find the corresponding y-values:
When x = 0:
y = -3(0) + 2
y = 2
So one point on the graph is (0, 2).
When x = 1:
y = -3(1) + 2
y = -3 + 2
y = -1
So another point on the graph is (1, -1).
When x = -1:
y = -3(-1) + 2
y = 3 + 2
y = 5
So another point on the graph is (-1, 5).
Now we can plot these points and draw a line through them:
(0, 2)
(1, -1)
(-1, 5)
The graph should have a negative slope (-3) and intersect the y-axis at (0, 2). It will look like a downward slanting line from left to right.
One way to plot points is by substituting values of x into the equation and calculating the corresponding y-values.
Let's choose a few values for x and find the corresponding y-values:
When x = 0:
y = -3(0) + 2
y = 2
So one point on the graph is (0, 2).
When x = 1:
y = -3(1) + 2
y = -3 + 2
y = -1
So another point on the graph is (1, -1).
When x = -1:
y = -3(-1) + 2
y = 3 + 2
y = 5
So another point on the graph is (-1, 5).
Now we can plot these points and draw a line through them:
(0, 2)
(1, -1)
(-1, 5)
The graph should have a negative slope (-3) and intersect the y-axis at (0, 2). It will look like a downward slanting line from left to right.
Is this the correct graph of y=−13x+4?(1 point)
Responses
Yes, it is the correct graph because this graph has a y-intercept of (0,4).
Yes, it is the correct graph because this graph has a y -intercept of left parenthesis 0 comma 4 right parenthesis .
Yes, it is the correct graph because this graph has a y-intercept of (0,3).
Yes, it is the correct graph because this graph has a y -intercept of left parenthesis 0 comma 3 right parenthesis .
No, it is not the correct graph because this graph has a positive slope.
No, it is not the correct graph because this graph has a positive slope.
No, it is not the correct graph because this graph used (0,3) as the y-intercept.
Responses
Yes, it is the correct graph because this graph has a y-intercept of (0,4).
Yes, it is the correct graph because this graph has a y -intercept of left parenthesis 0 comma 4 right parenthesis .
Yes, it is the correct graph because this graph has a y-intercept of (0,3).
Yes, it is the correct graph because this graph has a y -intercept of left parenthesis 0 comma 3 right parenthesis .
No, it is not the correct graph because this graph has a positive slope.
No, it is not the correct graph because this graph has a positive slope.
No, it is not the correct graph because this graph used (0,3) as the y-intercept.
No, it is not the correct graph because this graph has a positive slope.
Graph the linear equation
y=23x−1.
y=23x−1.
To graph the equation y = 23x - 1, we can plot a few points and then connect them to form a line.
Let's choose a few values for x and find the corresponding y-values:
When x = 0:
y = 23(0) - 1
y = 0 - 1
y = -1
So one point on the graph is (0, -1).
When x = 1:
y = 23(1) - 1
y = 23 - 1
y = 22
So another point on the graph is (1, 22).
When x = -1:
y = 23(-1) - 1
y = -23 - 1
y = -24
So another point on the graph is (-1, -24).
Now we can plot these points and draw a line through them:
(0, -1)
(1, 22)
(-1, -24)
The graph should have a positive slope (23) and intersect the y-axis at (0, -1). It will look like an upward slanting line from left to right.
Let's choose a few values for x and find the corresponding y-values:
When x = 0:
y = 23(0) - 1
y = 0 - 1
y = -1
So one point on the graph is (0, -1).
When x = 1:
y = 23(1) - 1
y = 23 - 1
y = 22
So another point on the graph is (1, 22).
When x = -1:
y = 23(-1) - 1
y = -23 - 1
y = -24
So another point on the graph is (-1, -24).
Now we can plot these points and draw a line through them:
(0, -1)
(1, 22)
(-1, -24)
The graph should have a positive slope (23) and intersect the y-axis at (0, -1). It will look like an upward slanting line from left to right.
3 answers