Given the equation x^2+y^2-8x-6y=0

Question

(a.) Write the equation in standard form .
(b.) State the center, radius, and intercepts.

Answer 1

(x^2 - 8x) + (y^2 - 6y) = 0
(x^2 - 8x + 16) + (y^2 - 6y + 9) = 16+9
(x-4)^2 + (y-3)^2 = 5^2

you can prolly get the other answers ok now, yeah?

Answer 2

yeah thanks