To rewrite the given equation 5x^2 − 20x + 15 = 0 in vertex form, we first need to complete the square.
5x^2 − 20x + 15 = 0
5(x^2 − 4x) = -15
5(x^2 − 4x + 4) = -15 + 20
5(x^2 − 4x + 4) = 5
The equation is now in the form a(x − h)^2 + k = 0. Comparing this form to the given equation, we find that h = 2 and k = 5.
Therefore, the correct answer is: h = 2, k = 5.
Given the equation 5x2 − 20x + 15 = 0, what are the values of h and k when the equation is written in vertex form a(x − h)2 + k = 0?
h = 2, k = 17
h = 2, k = −5
h = 1, k = 3
h = −1, k = −3
1 answer