2x - 8y = 8.
The x-int. is the value of x when Y = 0:
2x - 8*0 = 8
2x = 8
X = 4 = x-int.
(4,0).
The y-int. is the value of Y when x = 0:
2*0 - 8y = 8
-8y = 8
Y = -1 = y-int.
(0,-1).
given the equation 2x-8y=8, determine as coordinates
(a)the x intercept (b) the y intercept
A (a)(0,0) B (a)(-4,0) C(a)(4,0)
(b)(0,1) (b)(0,-1) (b)(0,-1)
D (a)(-1,0)
(b)(0,4)
would it be a,b,c,d and how did you get it
1 answer