given the equation 2x-4y=12 give x and y intercepts write in ordered pairs

Answer 1

To find the x-intercept and y-intercept of the equation \(2x - 4y = 12\), we can follow these steps:

1. Finding the x-intercept: Set \(y = 0\) and solve for \(x\). \[ 2x - 4(0) = 12 \ 2x = 12 \ x = 6 \] The x-intercept is \((6, 0)\).

2. Finding the y-intercept: Set \(x = 0\) and solve for \(y\). \[ 2(0) - 4y = 12 \ -4y = 12 \ y = -3 \] The y-intercept is \((0, -3)\).

Therefore, the x-intercept is \((6, 0)\) and the y-intercept is \((0, -3)\).

Answer 2

or, just use the intercept form. Divide by 12 to get
2x-4y=12
x/6 - y/3 = 1
So the intercepts are (6,0) and (0,3)

Answer 3

It looks like there was a small mistake in your last step regarding the y-intercept. When you express the equation in standard intercept form, the correct conversion is as follows:

Starting from your equation:

1. Rewrite the original equation:

\[ 2x - 4y = 12 \]

2. Divide the entire equation by 12:

\[ \frac{2x}{12} - \frac{4y}{12} = 1 \]

This simplifies to:

\[ \frac{x}{6} - \frac{y}{3} = 1 \]

3. This can be rewritten as:

\[ \frac{x}{6} + \frac{y}{-3} = 1 \]

From this form, we can clearly see the intercepts:

• The x-intercept, where \(y = 0\), is \((6, 0)\).
• The y-intercept, where \(x = 0\), is \((0, -3)\).

Make sure to note that the y-intercept is \((0, -3)\), not \((0, 3)\).

So the final intercepts remain as:

• x-intercept: \((6, 0)\)
• y-intercept: \((0, -3)\)

Answer 4

right you are. I didn't watch the signs.
x/6 + y/-3 = 1
gives the correct intercepts.

Answer 5

Yes, no worries! It's easy to miss signs, especially when working with intercept forms.

Just to summarize clearly: from the equation

\[ \frac{x}{6} + \frac{y}{-3} = 1 \]

we correctly derive the intercepts:

• x-intercept: Set \(y = 0\), which gives \(x = 6\), resulting in the point \((6, 0)\).
• y-intercept: Set \(x = 0\), which gives \(y = -3\), resulting in the point \((0, -3)\).

So, the intercepts are indeed \((6, 0)\) and \((0, -3)\). If you have any more questions or need further clarification, feel free to ask!