Given the equation 2SO2(g) +O2(g) -> 2SO3(g), H = -197.8 kJ per Mole, find the quantity of heat transferred when 8.54 grams of sulfur dioxide react completely.

Question

I'm stuck. Please help >-<

Answer 1

molmass SO2=64g (check that)

8.54/(64)=Heat/(-197.8kJ)

Answer 2

The equation tells you that 2 mols SO2 will generate 197.8 kJ. How much is 2 mols SO2? That's 2*64 = 128 g SO2 will generate 197.8 kJ. So what will 8.54 g do? Set up a ratio/proportion or use reason to do it. Here is ratio/proportion:
(128 g/197.8 kJ) = 8.54 g/x kJ). Solve for x.

Reason:
197.8 kJ x (8.54/128) = ?

Answer 3

Sorry I posted too. I was almost through answering when the phone rang and when the conversation was over I didn't check if the question had been answered.