To find \((g \circ f)(-3)\), we first need to evaluate \(f(-3)\) and then use this result to evaluate \(g\).
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Calculate \(f(-3)\): \[ f(x) = x^2 + 5x + 9 \] Substituting \(-3\) for \(x\): \[ f(-3) = (-3)^2 + 5(-3) + 9 \] Calculating each term: \[ = 9 - 15 + 9 \] \[ = 9 - 15 + 9 = 3 \]
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Now calculate \(g(f(-3)) = g(3)\): \[ g(x) = 4x - 10 \] Substituting \(3\) for \(x\): \[ g(3) = 4(3) - 10 \] \[ = 12 - 10 = 2 \]
Thus, the value of \((g \circ f)(-3)\) is: \[ \boxed{2} \]