To find \((g \circ f)(-2)\), we need to first evaluate \(f(-2)\) and then use that result to evaluate \(g(f(-2))\).
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Evaluate \(f(-2)\): \[ f(x) = 2x^2 - 3x - 10 \] Thus, \[ f(-2) = 2(-2)^2 - 3(-2) - 10 \] Calculating this step-by-step: \[ = 2(4) + 6 - 10 \] \[ = 8 + 6 - 10 \] \[ = 4 \]
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Now evaluate \(g(f(-2))\), which is \(g(4)\): \[ g(x) = 4x - 11 \] Thus, \[ g(4) = 4(4) - 11 \] Calculating this: \[ = 16 - 11 \] \[ = 5 \]
Therefore, the value of \((g \circ f)(-2)\) is \(\boxed{5}\).