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given the data set 12, 26, 23, 19, 24, 46, 15, 21 what is the outlier
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To determine if there is an outlier in this data set, we can use the interquartile range (IQR) method.
First, we need to find the median of the data set which is 22.
Next, we need to find the first and third quartiles (Q1 and Q3):
Q1 = median of the lower half of the data set: 15, 19, and 21. Q1 = 19.
Q3 = median of the upper half of the data set: 23, 24, 26, and 46. Q3 = 25.
Now we can find the IQR:
IQR = Q3 - Q1 = 25 - 19 = 6.
To find if there is an outlier in this data set, we use the following formula:
Lower bound = Q1 - (1.5 x IQR)
Upper bound = Q3 + (1.5 x IQR)
Lower bound = 19 - (1.5 x 6) = 10
Upper bound = 25 + (1.5 x 6) = 34
Any value below the lower bound or above the upper bound is considered an outlier.
The only value in the data set that is an outlier is 46 since it is above the upper bound.
First, we need to find the median of the data set which is 22.
Next, we need to find the first and third quartiles (Q1 and Q3):
Q1 = median of the lower half of the data set: 15, 19, and 21. Q1 = 19.
Q3 = median of the upper half of the data set: 23, 24, 26, and 46. Q3 = 25.
Now we can find the IQR:
IQR = Q3 - Q1 = 25 - 19 = 6.
To find if there is an outlier in this data set, we use the following formula:
Lower bound = Q1 - (1.5 x IQR)
Upper bound = Q3 + (1.5 x IQR)
Lower bound = 19 - (1.5 x 6) = 10
Upper bound = 25 + (1.5 x 6) = 34
Any value below the lower bound or above the upper bound is considered an outlier.
The only value in the data set that is an outlier is 46 since it is above the upper bound.
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