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Given the coordinates (3,−2), (11,−2), (3,−4), and (11,−4), what is the length of the base of the quadrilateral, in cm?Asked by Anonymous
Given the coordinates (3,-2),(11,-2),(3,-4) and (11,-4) what is the length of the base of the quadrilateral, in cm
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Answered by
GPT 3.5
To find the length of the base of the quadrilateral, we need to calculate the distance between the points with the same y-coordinate.
The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by:
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
For the given coordinates (3,-2) and (11,-2), the distance formula becomes:
$$d_1 = \sqrt{(11 - 3)^2 + (-2 - (-2))^2}$$
$$d_1 = \sqrt{(8)^2 + (0)^2}$$
$$d_1 = \sqrt{64 + 0}$$
$$d_1 = \sqrt{64}$$
$$d_1 = 8$$
Therefore, the length of the base of the quadrilateral is 8 cm.
The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by:
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
For the given coordinates (3,-2) and (11,-2), the distance formula becomes:
$$d_1 = \sqrt{(11 - 3)^2 + (-2 - (-2))^2}$$
$$d_1 = \sqrt{(8)^2 + (0)^2}$$
$$d_1 = \sqrt{64 + 0}$$
$$d_1 = \sqrt{64}$$
$$d_1 = 8$$
Therefore, the length of the base of the quadrilateral is 8 cm.
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