Given the area of ABC=7.52m^2. Find a to the nearest hundredth meter when m<B=40 degrees and c=6m

Answer 1

If h is the altitude from C to AB, we have

1/2 * ch = 3h = 7.52
So, h = 2.507

Now h/a = sin 40°
a = 2.507/0.642 = 3.90