change to standard form:
x^2/4 - y^2/9 = 1
a = 2
b = 3
c^2 = 4+9 = 13
c = √13
(i) center: (0,0)
vertices: (±2,0)
(ii) foci at (±√13,0)
(iii) asymptotes: y = ±3/2 x
Given that the equation of the hyperbola is 9x(squared)-4y(squared)=36.
(i)Find the centre and vertices
(ii)Find the foci and eccentricity
(iii)find the equation of the asymptotes
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